3x^2+8x-24=936

Solution for 3x^2+8x-24=936 equation:

3x^2+8x-24=936

We move all terms to the left:

3x^2+8x-24-(936)=0

We add all the numbers together, and all the variables

3x^2+8x-960=0

a = 3; b = 8; c = -960;
Δ = b2-4ac
Δ = 82-4·3·(-960)
Δ = 11584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11584}=\sqrt{64*181}=\sqrt{64}*\sqrt{181}=8\sqrt{181}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{181}}{2*3}=\frac{-8-8\sqrt{181}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{181}}{2*3}=\frac{-8+8\sqrt{181}}{6}
$